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Copy pathL857-MinimumCostToHireKWorkers.java
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L857-MinimumCostToHireKWorkers.java
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// https://leetcode.com/problems/minimum-cost-to-hire-k-workers/
class Solution {
public double mincostToHireWorkers(int[] quality, int[] wage, int k) {
int n = quality.length, currentTotalQuality = 0;
double totalCost = Double.MAX_VALUE;
List<Pair<Double, Integer>> wageToQualityRatio = new ArrayList<>();
for (int i = 0; i < n; i++) {
wageToQualityRatio.add(
new Pair<>((double) wage[i] / quality[i], quality[i])
);
}
Collections.sort(wageToQualityRatio, Comparator.comparingDouble(Pair::getKey));
PriorityQueue<Integer> highestQualityWorkers = new PriorityQueue<>(Collections.reverseOrder());
for (int i = 0; i < n; i++) {
highestQualityWorkers.add(wageToQualityRatio.get(i).getValue());
currentTotalQuality += wageToQualityRatio.get(i).getValue();
int size = highestQualityWorkers.size();
if (size > k) {
currentTotalQuality -= highestQualityWorkers.poll();
size -= 1;
}
if (size == k) {
totalCost = Math.min(totalCost, currentTotalQuality * wageToQualityRatio.get(i).getKey());
}
}
return totalCost;
}
}