[pre-commit.ci] auto fixes from pre-commit.com hooks

for more information, see https://pre-commit.ci

Author: pre-commit-ci[bot]

content/6_Advanced/Lagrange.mdx

@@ -121,43 +121,43 @@ using namespace std;
 #define ll long long
 
 int main() {
-    int n, k;
-    cin >> n >> k;
-
-    int a[n];
-    for (int &i : a) { cin >> i; }
-
-    /*
-     * Returns {maximum sum, subarrays used (max if ties)} 
-     * if creating a subarray penalizes the sum by "lmb" and 
-     * there is no limit to the number of subarrays you can create
-    */
-    auto solve_lambda = [&](ll lmb) {
-        pair<ll, ll> dp[n][2];
-
-        dp[0][0] = {0, 0}; 
-        dp[0][1] = {a[0] - lmb, 1};
-    
-        for (int i = 1; i < n; i++){
-            dp[i][0] = max(dp[i - 1][0], dp[i - 1][1]);
-
-            dp[i][1] = max(
-                make_pair(dp[i - 1][0].first + a[i] - lmb, dp[i - 1][0].second + 1), 
-                make_pair(dp[i - 1][1].first + a[i], dp[i - 1][1].second)
-            );
-        }
-
-        return max(dp[n - 1][0], dp[n - 1][1]);
-    };
-    
-    ll lo = 0; 
-    ll hi = 1e18;
-    while (lo < hi) {
-        ll mid = (lo + hi) / 2;
-        solve_lambda(mid).second <= k ? hi = mid : lo = mid + 1;
-    }
-
-    cout << solve_lambda(lo).first + lo * k << endl;
+	int n, k;
+	cin >> n >> k;
+
+	int a[n];
+	for (int &i : a) { cin >> i; }
+
+	/*
+	 * Returns {maximum sum, subarrays used (max if ties)}
+	 * if creating a subarray penalizes the sum by "lmb" and
+	 * there is no limit to the number of subarrays you can create
+	 */
+	auto solve_lambda = [&](ll lmb) {
+		pair<ll, ll> dp[n][2];
+
+		dp[0][0] = {0, 0};
+		dp[0][1] = {a[0] - lmb, 1};
+
+		for (int i = 1; i < n; i++) {
+			dp[i][0] = max(dp[i - 1][0], dp[i - 1][1]);
+
+			dp[i][1] =
+			    max(make_pair(dp[i - 1][0].first + a[i] - lmb,
+			                  dp[i - 1][0].second + 1),
+			        make_pair(dp[i - 1][1].first + a[i], dp[i - 1][1].second));
+		}
+
+		return max(dp[n - 1][0], dp[n - 1][1]);
+	};
+
+	ll lo = 0;
+	ll hi = 1e18;
+	while (lo < hi) {
+		ll mid = (lo + hi) / 2;
+		solve_lambda(mid).second <= k ? hi = mid : lo = mid + 1;
+	}
+
+	cout << solve_lambda(lo).first + lo * k << endl;
 }
 ```