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solutions/bronze/usaco-808.mdx

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@@ -154,6 +154,7 @@ So, each time this occurs we can count it and return this total count as our ans
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We can do this first by finding which cow, if any, every cow passes the ball to.
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## Implementation
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**Time Complexity:** $\mathcal{O}(N^2)$
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<LanguageSection>
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print(ans)
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```
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</PySection>
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<CPPSection>
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```
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</CPPSection>
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<JavaSection>
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```java
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io.println(ballsNeeded);
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io.close();
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}
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// CodeSnip{Kattio}
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//CodeSnip{Kattio}
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}
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```
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```
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</JavaSection>
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</LanguageSection>
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</Spoiler>

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