实现一个 Trie (前缀树),包含 insert
, search
, 和 startsWith
这三个操作。
示例:
Trie trie = new Trie(); trie.insert("apple"); trie.search("apple"); // 返回 true trie.search("app"); // 返回 false trie.startsWith("app"); // 返回 true trie.insert("app"); trie.search("app"); // 返回 true
说明:
- 你可以假设所有的输入都是由小写字母
a-z
构成的。 - 保证所有输入均为非空字符串。
题目标签:Design / Trie
题目链接:LeetCode / LeetCode中国
Language | Runtime | Memory |
---|---|---|
java | 74 ms | 52.2 MB |
class Trie {
class TrieNode {
int path;
int end;
TrieNode map[];
TrieNode() {
path = 0;
end = 0;
map = new TrieNode[26];
}
}
TrieNode root;
/** Initialize your data structure here. */
public Trie() {
root = new TrieNode();
}
/** Inserts a word into the trie. */
public void insert(String word) {
char[] w = word.toCharArray();
TrieNode node = root;
int index = 0;
for (int i = 0; i< w.length; i++) {
index = w[i] - 'a';
if (node.map[index] == null) {
node.map[index] = new TrieNode();
}
node = node.map[index];
node.path++;
}
node.end++;
}
/** Returns if the word is in the trie. */
public boolean search(String word) {
char[] w = word.toCharArray();
TrieNode node = root;
int index = 0;
for (int i = 0; i < w.length; i++) {
index = w[i] - 'a';
if (node.map[index] == null) {
return false;
}
node = node.map[index];
}
return node.end > 0;
}
/** Returns if there is any word in the trie that starts with the given prefix. */
public boolean startsWith(String prefix) {
char[] w = prefix.toCharArray();
TrieNode node = root;
int index = 0;
for (int i = 0; i < w.length; i++) {
index = w[i] - 'a';
if (node.map[index] == null) {
return false;
}
node = node.map[index];
}
return true;
}
}
/**
* Your Trie object will be instantiated and called as such:
* Trie obj = new Trie();
* obj.insert(word);
* boolean param_2 = obj.search(word);
* boolean param_3 = obj.startsWith(prefix);
*/