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nth_prime_power.sf
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#!/usr/bin/ruby
# Daniel "Trizen" Șuteu
# Date: 07 July 2022
# https://github.com/trizen
# Compute the n-th prime power, using binary search and the prime-power counting function.
# See also:
# https://oeis.org/A143039
func prime_power_count_lower(n) {
sum(1..n.ilog2, {|k|
prime_count_lower(n.iroot(k))
})
}
func prime_power_count_upper(n) {
sum(1..n.ilog2, {|k|
prime_count_upper(n.iroot(k))
})
}
func nth_prime_power_lower(n) {
bsearch_min(n, n.nth_prime_upper, {|k|
prime_power_count_upper(k) <=> n
})
}
func nth_prime_power_upper(n) {
bsearch_max(n, n.nth_prime_upper, {|k|
prime_power_count_lower(k) <=> n
})
}
func nth_prime_power(n) {
n == 0 && return 1 # not a prime power, but...
n <= 0 && return NaN
n == 1 && return 2
var min = nth_prime_power_lower(n)
var max = nth_prime_power_upper(n)
var k = 0
var c = 0
loop {
k = (min + max)>>1
c = prime_power_count(k)
if (abs(c - n) <= n.iroot(3)) {
break
}
given (c <=> n) {
when (+1) { max = k-1 }
when (-1) { min = k+1 }
else { break }
}
}
while (!k.is_prime_power) {
--k
}
while (c != n) {
var j = (n <=> c)
k += j
c += j
k += j while !k.is_prime_power
}
return k
}
for n in (1..10) {
var pp = nth_prime_power(10**n)
assert(pp.is_prime_power)
assert_eq(pp.prime_power_count, 10**n)
assert_eq(10**n -> nth_prime_power, pp)
say "PP(10^#{n}) = #{pp}"
}
assert_eq(
nth_prime_power.map(1..100),
100.by { .is_prime_power }
)
__END__
PP(10^1) = 16
PP(10^2) = 419
PP(10^3) = 7517
PP(10^4) = 103511
PP(10^5) = 1295953
PP(10^6) = 15474787
PP(10^7) = 179390821
PP(10^8) = 2037968761
PP(10^9) = 22801415981
PP(10^10) = 252096675073
PP(10^11) = 2760723662941
PP(10^12) = 29996212395727
PP(10^13) = 323780470283789
PP(10^14) = 3475385632514321
PP(10^15) = 37124507635789309