|
| 1 | +"""Return the index of the first occurrence of needle in haystack, |
| 2 | +or -1 if needle is not part of haystack. |
| 3 | +
|
| 4 | +For the purpose of this problem, we will return 0 when needle is an empty string. |
| 5 | +
|
| 6 | +""" |
| 7 | + |
| 8 | + |
| 9 | +class Solution: |
| 10 | + def strStr(self, haystack: str, needle: str) -> int: |
| 11 | + |
| 12 | + if not needle: |
| 13 | + return 0 |
| 14 | + |
| 15 | + if len(needle) > len(haystack): |
| 16 | + return -1 |
| 17 | + |
| 18 | + if len(needle) == len(haystack): |
| 19 | + if needle == haystack: |
| 20 | + return 0 |
| 21 | + return -1 |
| 22 | + |
| 23 | + for i in range(len(haystack) - len(needle) + 1): |
| 24 | + |
| 25 | + first_j = i |
| 26 | + |
| 27 | + for j in range(len(needle)): |
| 28 | + |
| 29 | + if first_j == len(haystack): |
| 30 | + break |
| 31 | + |
| 32 | + if haystack[first_j] != needle[j]: |
| 33 | + break |
| 34 | + |
| 35 | + first_j += 1 |
| 36 | + |
| 37 | + if first_j - i == len(needle): |
| 38 | + return i |
| 39 | + |
| 40 | + return -1 |
| 41 | + |
| 42 | + |
| 43 | +if __name__ == "__main__": |
| 44 | + |
| 45 | + sol = Solution() |
| 46 | + |
| 47 | + assert sol.strStr("aaa", "aaaa") == -1 |
| 48 | + assert sol.strStr("mississippi", "issip") == 4 |
| 49 | + assert sol.strStr("hello", "ll") == 2 |
| 50 | + assert sol.strStr("aaa", "aaa") == 0 |
| 51 | + assert sol.strStr("a", "a") == 0 |
| 52 | + assert sol.strStr("aaa", "aaa") == 0 |
| 53 | + assert sol.strStr("ba", "a") == 1 |
| 54 | + assert sol.strStr("aaaaa", "bba") == -1 |
| 55 | + assert sol.strStr("", "") == 0 |
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